11. in order to move a 7.5 HC charge from negative to pove capacitor of with 5.w
ID: 3308430 • Letter: 1
Question
11. in order to move a 7.5 HC charge from negative to pove capacitor of with 5.we need to apply aforceof30N.Whtste poten difterence across the capacitor pliates? A 3.75V 8.25V C2V D 225 E15V 2. How much work is done by a niorm 300 N ec ed on a chage of aI mCin accelerating in thru a distance of 0.20m 13. A solid conducting sphere is givan apositive charge Q How is tde g distribuned in or on the sphere? 4030C b. Ifql is removed, Find the magnitade and direction of the eletarl field at poins s where the q1 used so be 0.20 4.0CExplanation / Answer
11. F = q E
3 = (7.5 x 10^-6) E
E = 400000 V/m
delta(V) = Ed = (400000)(5 x 10^-6)
= 2 Volt
Ans(C)
12. Work done = q delta(V)
= q E D
= (6.1 x 10^-3) (300) (0.20)
= 3.66 x 10^-1 J
13. (E) On conductor, charge always resides on surface.
(A) F = kq1 q2 /d^2
= (9 x 10^9 x 4 x 10^-6 x 3 x 10^-6) / 0.20^2
= 2.7 N
(B) E = k q / r^2 = (9 x 10^0 x 4 x 10^-6) / 0.2^2
= 9 x10^5 N/C
to the left .
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