Capacitance Question (a) A 1 nF capacitor is charged to ± Q = 1 µ C on its two c

Question

Capacitance Question
(a) A 1 nF capacitor is charged to ±Q = 1 µC on its two conductors. What is the potential difference between the conductors?
(b) By changing the geometry of the conductors the capacitance is increased by a factor 1000 to 1 µF, without allowing charge to flow either on or off the conductors. What happens to the potential difference? What proportionality is illustrated here?
(c) How much does the stored energy change in the process (a)(b)? What proportionality is illustrated?
Capacitance Question
(a) A 1 nF capacitor is charged to ±Q = 1 µC on its two conductors. What is the potential difference between the conductors?
(b) By changing the geometry of the conductors the capacitance is increased by a factor 1000 to 1 µF, without allowing charge to flow either on or off the conductors. What happens to the potential difference? What proportionality is illustrated here?
(c) How much does the stored energy change in the process (a)(b)? What proportionality is illustrated?
Capacitance Question
(a) A 1 nF capacitor is charged to ±Q = 1 µC on its two conductors. What is the potential difference between the conductors?
(b) By changing the geometry of the conductors the capacitance is increased by a factor 1000 to 1 µF, without allowing charge to flow either on or off the conductors. What happens to the potential difference? What proportionality is illustrated here?
(c) How much does the stored energy change in the process (a)(b)? What proportionality is illustrated?

Explanation / Answer

(A) V = Q / C

V = (1 x 10^-6 C) / (1 x 10^-9 F) = 1000 Volt

(B) charge is constant so,

C V = constant

(1 x 10^-9 F) (1000 V) = (1 x 10^-6) (V)

V = 1 Volt

(C) U = Q^2 / 2 C

U C = Q^2 /2 = constant

C inctease by 1000 times.

hence energy decreases by 1000 times.

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