Short answer Panther ID 7564 ve that best completes the statement 1. Choose the

Question

Short answer Panther ID 7564 ve that best completes the statement 1. Choose the one alternative late capacitor with the plate separation of 6 cm is 0 v 1) The potential diference between the plates of a parallel What is the electric field between the plates of this ca apacitor?pacitor C) 2000 V/m B)1000 V/m D) 60 Vim lates. The electric potential energy stored in this of 20 Vbetween its electric D)800 ! When two point charges are a distance d electric fo F. In order to make this or twicr as strong the distance would have to nart, the electric force that each one feels from the other has magnitude D) 24 B) d/4 A)42 Two conductors arejoined by a long copper wire. Thus A) the electric field at the surface of each conductor is the same. B) no free charge can be present on either conductor O the potential on the wire is the average of the potential of each conductor D each carries the same free charge. each conductor must be at the same potential. 5) An electron is released from rest at a distance of 9 cm from a proton. How fast in m/s will the electron be moving when it is 3 cm from the proton? A) 75 B) 1.06x 103 C) 130 D) 4.64 105 E 106 ) Whut is the eletric feld 0.0001 m, y = 0 m and tether atr=-0001 m, y = 0 m? SPNC B)288x 10-19 N/C A darged particle with charge +5.0 uC at rest. D)ONC C)5.76 × 10-19N/C A)290, etic energy of thisa si itially at rest. It is accelerated through a potential difference of 500 What is the A)2500 J/m article? B) 2.5- 10-3 D) 25-10-3Jm C) 2500J patte charge? strngh of an electrilt 28 1015 NIC ta 0.010 C negative charge experiences 0.80 mm from a 0,20 C negative D) 28 1016 N/C B)7.0 1016 N/C C) 1.4 1015 N/C Polet charge Q is located a short distance tial force on Qis F, the ele present. If the ce from a point charge 30, and no other charges are

Explanation / Answer

1) E = V / d = 60 / 0.06 = 1000 V./m 0 Ans(B)

2) U = C V^2 /2 = (4uF)(20^2 / 2) = 800 uJ  

Ans(D)

3) F = k q1 q2 / d^2

F2 / F1 = (d1 / d2 )^2 we want F2 = 2 F1

d1 /d2 = sqrt(2) =

d2 = d1/ sqrt(2)

Ans(E)

4. (D)  

5. Pei + KEi = PEf + Kef

- (9 x 10^9x (1.6x 10^-19)^2)/0.09 + 0 = - (9 x 10^9x (1.6x 10^-19)^2)/0.03 + (9.109 x 10^-31)v^2 /2

v = 106 m/s

Ans(E)

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