The table below is based on results described in a study that examined the effec
ID: 3309454 • Letter: T
Question
The table below is based on results described in a study that examined the effects of alcohol consumption and drug use on sexual behavior, for undergraduate students at a university in the southeastern United States. In this table, the columns refer to whether the student engaged in unprotected sex in the past three months, and the rows refer to whether the student reported drinking alcohol mixed with energy drinks (AmED) (q.10).
a) Construct conditional distributions that treat unprotected sex as the response variable. Interpret.
b) Test whether the variables are statistically independent. Report the P-value, and interpret.
Unprotected Sex
Yes
No
AmED
Yes
77
44
Consumption
No
194
309
11). The World Values Survey asks many questions relevant to social scientists. You will construct a bit of your own question here. Click the 2010-2014 wave and choose at least two additional countries besides the US. Go online to see responses to the following question: V12.- Important child qualities: independence. //www.worldvaluessurvey.org/WVSOnline.jsp}
Provide the summary table here
Interpret the table from above
How might you analyze the above table? What tools do you have at your disposal?
Provide your analysis and interpret your results.
What avenues for future study would you consider, if any?
Summary of the table (Important child qualities: Independence)
Country Code
Ghana
Nigeria
TOTAL
Mentioned
28.8%
38.9%
38.9%
Not Mentioned
71.2%
61.1%
61.1%
(N)
(1,552)
(1, 759)
(3,311)
Selected samples: Ghana 201, Nigeria 2011
Yes
No
AmED
Yes
77
44
Consumption
No
194
309
Explanation / Answer
10)
p-value is very low . hence we reject the null and conclude that there is sufficient evidence that the variables are statistically independent.
c1 c2 total r1 77 44 121 r2 194 309 503 total 271 353 624 Oi 77 44 194 309 Ei 52.54968 68.45032 218.4503 284.5497 TS (O--Ei)^2/Ei 11.37625 8.733607 2.736632 2.100927 24.94741 critical value 3.84 p-value 5.89155E-07Related Questions
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