The estimated proportion of students who take an online course is 10%. If you wa
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Question
The estimated proportion of students who take an online course is 10%. If you want to be 85% confident that the sample mean is within 8% of the population mean, how many students must be surveyed?
The number of coins a person carries is normally distributed with an unknown population mean. A random sample of 250 shoppers at the mall were asked how many coins they had on them. The average was 57 coins with a standard deviation of 5.6 coins. Find the 98% confidence interval for the mean number of coins a person carries.
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Office workers were interviewed to determine how much training they received when they were hired at the company. A survey of 8 new hires revealed a mean of 6.75 hours of training with a standard deviation of 1.48 hours. You have no other information about the distribution of the population data. Find the 98% confidence interval for the mean number of hours of training provided to new hires.
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A simple random sample of electronic components produced by a certain method is performed. Assume that the component lifetimes are normally distributed with a population standard deviation of = 20 hours. Find the sample size needed so that a 99% confidence interval will have a margin of error of 3.
You are an efficiency expert is looking at the number of pens in a typical office desk. The standard deviation of the number of pens is known to be 37. How many desks must be inventoried to be 95% certain that you are within 10 pens of the mean?
The number of hours people listen to the radio is normally distributed with an unknown population mean and a population standard deviation of 0.75 hours. A random sample of 81 people are surveyed and asked how many hour they listen to the radio daily and gives a sample mean of 2.5 hours. Find a 90% confidence interval for the population mean.
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In a sample of 423 Batavia male residents, it was found that 13.4% of those surveyed had served in the American military. Find the 98% confidence interval for the proportion of males in Batavia who served in the American military.
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Show your answer to 2 decimal places. Do not enter the leading zero.
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Given CI Level 85% p 0.1 ME 0.08 z-value of 85% CI 1.4395 n = (z/ME)^2*p*(1-p) 29Related Questions
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