The data show the bug chirps per minute at different temperatures. Find the regr
ID: 3309887 • Letter: T
Question
The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 750 895 808 1024 1231 1040 Temperature (degrees°F) 70.9 77.9 74 76.7 87.4 80.9 ^y= _____ + _____ (Round the x-coefficient to four decimal places as needed. Round the constant to two decimals as needed) What is the predicted value? ^y= _____ (Round to one decimal places as needed) What is wrong with this predicted value? A. The first variable should have been the dependent variable B. It is unrealistically high. C. It is only an approximation D. Nothing is wrong with this value
Explanation / Answer
Solution:-
=> The regression equation ^y = 48.36 + 0.031x
=> ^y = 141.4
Explanation:- ^y = 48.36 + 0.031x
^y = 48.36 + 0.031(3000)
^y = 141.36
=> option B. It is unrealistically high
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.