np Chorees te Points Fach) hapter 8 then the mean and the andard deviation for t
ID: 3310012 • Letter: N
Question
np Chorees te Points Fach) hapter 8 then the mean and the andard deviation for the sampling distribution of X for n = 16 are: 4 and 1 . 12 and 4 . 48 and 4 . 48 and 1 . 48 and 16 the . A manufacturing company measures the weight of boxes before shipping them to customers. If the box weights have a population mean and standard deviation of 90 Ibs. bs. respectively, then based on a sample size of 36 boxes, of the boxes will exceed 94 lbs. is: A. 34.13% B. 84.13% C. 15.87% D. 56.36% E. 16.87% the probability that the average weight normal 3. Whenever the population has a normal distribution, the sampling distribution of X is or near normal distribution: A. For only large sample sizes B. For only small sample sizes C. For any sample size D. For only samples of size 30 or more 4. If a population distribution is known to be normal, then it follows that: A. The sample mean must equal the population mean B. The sample mean must equal the population mean for large samples C. The sample standard deviation must equal the population standard deviation D. All of the above E. None of the above 5. In a manufacturing process a machine produces bolts that have an average length of 3 inches with a variance of.03. If we randomly select three bolts from this process: What is the probability the mean length of the bolt is at least 3.1 inches? A. 84.13% B. 100% C. 71.57% D. 28.43% E. 15.87%Explanation / Answer
1) here mean of sampling distirbution =48
ands std error of mean =std deviation/(n)1/2 =16/(16)1/2 =4
therefore option C
2)
std error of mean =std deviation/(n)1/2 =24/(36)1/2 =4
therfore P(X>94)=P(Z>(94-90)/4)=P(Z>1) =15.87%
3)
option D is correct
4)
option E
5)
here std error of mean =(0.03/3)1/2 =0.1
therefore P(X>3.1)=P(Z>(3.1-3)/0.1)=P(Z>!) =15.87%
option E
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