Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A college professor collected information on 430 students including their year i

ID: 3310045 • Letter: A

Question

A college professor collected information on 430 students including their year in school (freshman, sophomore, junior and senior) and their current college GPA. The resulting data was used to create this ANOVA table. Several values have been deleted.

Source

DF

Sum of Squares

Mean Square

F Value

Pr > F

Model

3

0.996

0.332

CCC

0.3304

Error

426

BBB

0.290

Corrected Total

AAA

124.519


Use this ANOVA table to find the variance of the entire group of 430 students.

Source

DF

Sum of Squares

Mean Square

F Value

Pr > F

Model

3

0.996

0.332

CCC

0.3304

Error

426

BBB

0.290

Corrected Total

AAA

124.519

Explanation / Answer

variance of the entire group of 430 students.

from above annova table we can say that the mean square error is the variance of entire group

i.e 0.290

so variance = 0.29

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote