in Help I Use the normal distribution to find a confidence interval for a propor
ID: 3310114 • Letter: I
Question
in Help I Use the normal distribution to find a confidence interval for a proportion P given the relevant sample results. Give the best point estimate for P, the margin of error and the confidence interval. Assume the results come from a random sample. A 9 % confidence interval for the proportion who wil answer-Yes" to a queston, green that 62 answered yes in a random sample of 80 people Round your answers to three decimal places. point estimate 10.62 of error = ± | The 90% c to on Assistance, you will learn while you eam points based on the Point Potential Pocy set by your instructor Ean Maximum Points available only if you answer this question correctly in two 1/2620117Explanation / Answer
We need to calculate Point Estimate, Margin of Error and Confidence Interval at 90% confidence.
In a random sample of 80 people, 62 answered "Yes"
Point Estimate, p=62/80=0.775
Margin of Error=Z*sqrt[(p(1-p)/n)]
At 90% confidence, Z=1.645
MoE=1.645*sqrt[0.775*0.225/80)]=0.0766
Confidence Interval=p+-MoE=[p-MoE,p+MoE]=[0.6984,0.8516]
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