An online travel agent that specializes in cruises wanted to compare the cost of

Question

An online travel agent that specializes in cruises wanted to compare the cost of cruising to different destinations on varlous cruise Iines. The data show the average cost of a seven-day cruise in a standard room to two locations Assume the population variances for the cruise fares for those destinations are equal Complete parts a through c sample Location 2 $928 126 Location 1 Sample mean 989 Sample standard deviation 133 Sample size a. Construct a 95% confidence interval to estimate the difference between the average rates of cruising to location 1 vs. cruising to location 2 The 95% confidence interval is ). Round to two decimal places as needed) b. What conclusions can be made about the difference in rates between these destinations? with 95% confidence, it can be said that the difference in r that this interval c. What assumptions need to be made in order to perform this procedure? ates between these destinatos | the endpoints of the confidence interval The fact

Explanation / Answer

The statistical software output for this problem is:

Two sample T summary confidence interval:
1 : Mean of Population 1
2 : Mean of Population 2
1 - 2 : Difference between two means
(with pooled variances)

95% confidence interval results:

Hence,

a) 95% confidence interval will be:

(-65.39, 187.39)

b) Falls within; includes; is not

c) Option A is correct.

Difference Sample Diff. Std. Err. DF L. Limit U. Limit 1 - 2 61 59.907889 17 -65.394598 187.3946

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