(1) O more than O exactly O fewer than O at most O at least 6, A drug tester cla
ID: 3310383 • Letter: #
Question
(1) O more than O exactly O fewer than O at most O at least 6, A drug tester claims that a drug cures a rare skin disease 77% of the time. The claim is checked by testing the drug on 100 patients. If at least 71 patients are cured, the claim will be accepted. Find the probability that the claim will be rejected assuming that the manufacturer's claim is true. Use the normal distribution to approximate the binomial distribution if possible. The probability is The mean height of women in a country (ages 20-29) is 63.9 inches. A random sample of 70 women in this age group is (Round to four decimal places as needed.) 7. selected, what is the probability that the mean height for the sample is greater than 64 inches? Assume = 2.66. The probability that the mean height for the sample is greater than 64 inches is (Round to four decimal places as needed.) A population has a m ean-80 and a standard deviation -8. Find the mean and standard deviation of a sampling 8, distribution of sample means with sam ple size n = 64. (Simplify your answer.) (Simplify your answer.)Explanation / Answer
Solution:-
6. p = 0.77,n = 100,
=> mean = np = 100*0.77 = 77
sd = Sqrt(npq) = sqrt(100*0.77*0.23) = 4.2083
P(X 71) = P(Z (71 - 77)/4.2083)
= P(Z -1.4258)
= 0.9236
=> The probability is 0.9236
7. Given mean = 63.9 , sd = 2.66 , n = 70
P(X > 64) = P(Z > (64 - 63.9)/(2.66/sqrt(70)) )
= P(Z > 0.3145)
= 0.3783
=> The probability that the mean height for the sample is greater than 64 inches is 0.3783
8. given mean = 80 , sd = 8 , n = 64
=> 80
=> 8/sqrt(64) = 1
5. P(X< 88)
=> The probability of getting fewer than 88 success
=> option C. p(87.5 < X < 88.5)
(1) = option B.
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