1. Given the following information about glucose levels (in milligrams of glucos

ID: 3310498 • Letter: 1

Question

1. Given the following information about glucose levels (in milligrams of glucose per 100 milliliters of blood.) ( from 9.5)

73 61 104 75 85 65 62 98 92 106 ( Non pregnant women)

72 84 90 95 66 70 79 85 (pregnant women)

A. Find the sample standard deviation s of the non pregnant women sample

B. Find the sample standard deviation s of the pregnant women sample.

C. CLAIM: " The variance of the glucose test results for non pregnant women is different to the variance for pregnant women"

NOTATION: sigma squared is the population variance. (choose from 4 options below)

CLAIM: " The variance of the glucose test results for non pregnant women is different to the variance for pregnant women"

What is the final conclusion? (choose from 4 options below)

fail to reject the claim

Do heavy cars use more gasoline? Let x be the weight of a car, and y be the miles per gallon. (Chapter 10)

x: 27 44 32 47 23 40 34 52 ( hundreds of pounds)

y: 30 19 24 13 29 17 21 14 (miles per gallon)

A. Find the linear correlation coefficient r.

B. Find b sub zero and b sub 1. Which are needed for the linear correlation equation.

C. Use the linear correlation equation to predict the number of miles per gallon expected from a car that weighs38 hundred pounds.

sigma squared of non pregnant women is GREATER THAN sigma squared of non pregnant women

sample standar deviation of non-pregnant women

mean = 82.1

sd of non-preg = sqrt (sum of (indidual obs - 82.1) ^ 2 / (10-1) = 17.272)

17.27

sd of preg women is 10.19

claim is

variance of the glucose tests of non - pregnant women is different to the variance of the pregnant women

claim is actually the alternate hypothesis

notation is

c) sigma squared of non pregnant women is not equal to sigma squared of the pregnant women

it is given as non-pregant for the second part in the option b, correct it as pregnant.

p-value =1-F.DIST(2.8729,9,7,TRUE) = 0.089

since p-value is greater than 0.05 donot reject null hypothesis. Reject the claim.

Fail to support the claim

(nonpreg-mean nonpreg)^2 83 445 480 50 8 292 404 253 98 571 sum 2,685 sd

17.27

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