Also B) What is the probability that in the next 100,000 passengers the airline

Question

Also B) What is the probability that in the next 100,000 passengers the airline will have only one complaint?
C) What is the probability that in the next 100,000 passengers the airline will have 2 complaints?
Edit View History Bookmarks Window Help mathxl.com DS 2333 Fall 2017 Chris Mazza Homework: Extra Credit HW on Test 2 Material Score: 0 of 1 pt 20f 9 (4 complete) HW Score: 5.4.35-T In the first nine months of a year, airline consumer complaints were 0.95 per 100,000 passengers. Complete parts (a) through (c) below. a. What is the probability that in the next 100,000 passengers, the airline will have no complaints? The probability that the aine will have no complaints iD Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer Clear All Check a remaining 8

Explanation / Answer

pmf of P.D is = f ( k ) = e- x / x!
where
= parameter of the distribution.   
x = is the number of independent trials
I.
mean =
= 0.95
Part A.
P( X = 0 ) = e ^-0.95 * 0.95^0 / 0! = 0.38674
Part B.
P( X = 1 ) = e ^-0.95 * 0.95^1 / 1! = 0.3674
Part C.
P( X = 2 ) = e ^-0.95 * 0.95^2 / 2! = 0.17452

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