The population mean and standard deviation are given below. Find the required pr

Question

The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual. For a sample of n-66, find the probability of a sample mean being less than 22.1 if -22and .1.29. ] Click the icon to view page 1 of the standard normal table. Click the icon to view page 2 of the standard normal table. For a sample of n-66, the probablity of a sample mean being less than 22.1 if #22 and . 1.29 is (Round to four decimal places as needed.) Would the given sample mean be considered unusual? The sample mean I be cosidered unusual because it has a probability that is | than 5%.

Explanation / Answer

Solution:

Given in the question:

Population mean = 22

Xbar = 22.1

SD = 1.29

P(Xbar<22.1)=?

Z = 22.1-22/1.29 = 0.1/1.29 = 0.077

Probability can be fetch from standardized normal table ot Z table so

P(Xbar<22) = 0.5279 or 52.79%

so the sample is considered unusual becuase it has a probability 0.5279 than 0.05.

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