Homework: Lesson 6, Section 6.1 Homework Score: 0 of 1 pt 6.1.38 Save 60f 8 (0 c

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Homework: Lesson 6, Section 6.1 Homework Score: 0 of 1 pt 6.1.38 Save 60f 8 (0 complete) Hw Score: 0%, 0 of 8 pts E Question Help In a random sample of 35 refrigerators, the mean repair cost was $115.00 and the population standard deviat tion is $15.90. Construct a 90% confidence interval for the population mean repair cost. Interpret the results. Construct a 90% confidence interval for the population mean repair cost. The 90% confidence interval is (Round to two decimal places as needed ) Enter your answer in the edit fields and then click Check Answer Clear All Check Answer remaining Syllabus 28

Explanation / Answer

Mean is 115 and s is 15.9

for sample size of 35, the standard error SE=s/sqrt(N)=15.9/sqrt(35)=2.6876

for 90% confidence the z value is 1.65

upper limit is mean+z*SE=115+1.65*2.6876=119.43454

lower limit is mean-z*SE=115-1.65*2.6876=110.5655

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