Using the testing outout below construct a 95% confidence interval for the mean
ID: 3311725 • Letter: U
Question
Using the testing outout below construct a 95% confidence interval for the mean difference Hypothesis test results: -u2 : mean of the paired difference between wt 0.5 and Wt 1 Difference Sample Diff. Std. Err. DF T-Stat P-value wt 0.5 - Wt 1 1.090909 110.5323252 432.049328 0.0466 (OBSERVE that there is a DROP in the sample mean weights from week 0.5 and week 1). You will need to use a t-distribution with 43 degrees of freedom, the critical values are tabulated below probability 0.15 0.10 0.05 0.025 0.01 t 1.049 1.301.682.012.41 ,-) The 95% confidence interval for the mean difference in weight is [0 ± 2.01 x 0.53] The 95% confidence interval for the mean difference in weight is [0 ± 1.68 x 0.53] The 95% confidence interval for the mean difference in weight is [1.09 ± 2.01 x 0.53] The 95% confidence interval for the mean difference in weight is [1.09 ± 2.01 x 0.53/V44 The 95% confidence interval for the mean difference in weight is [1.09 ± 1.68× 0.531,Explanation / Answer
from above: sample differnce =1.09
for 95% CI ; at 43 df t =2.01
therefore 95% confidence interval for the mean difference in weight is 1.09 +/- 2.01*0.53
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