Consider the following contingency table of observed frequencies. Complete parts
ID: 3311743 • Letter: C
Question
Consider the following contingency table of observed frequencies. Complete parts a. through d. below.
Column Variable
Row Variable
Upper C 1C1
Upper C 2C2
Upper C 3C3
Upper R 1R1
9
7
11
Upper R 2R2
12
9
6
b, Calculate the expected frequencies for each cell in the contingency table.
Column Variable
Row Variable
Upper C 1C1
Upper C 2C2
Upper C 3C3
Upper R 1R1
nothing
nothing
nothing
Upper R 2R2
nothing
nothing
nothing
(Round to two decimal places as needed.)
c. Calculate the chi-square test statistic.
chi squared2equals=nothing
(Round to two decimal places as needed.)
d. Determine the p-value. Using
alphaequals=0.025
state your conclusions.
p-valueequals=nothing
(Round to three decimal places as needed.)
Column Variable
Row Variable
Upper C 1C1
Upper C 2C2
Upper C 3C3
Upper R 1R1
9
7
11
Upper R 2R2
12
9
6
Explanation / Answer
from above :
b)
c) applying chi square test:
chi-square test statistic. =2.15
d)
degree of freedom =(row-1)*(column-1) =(2-1)*(3-1) =2
for 2 df and above test statistic p value =0.341
for p value is greater then 0.025 level; can not reejct null hypothesis
Expected E=rowtotal*column total/grand total C1 C2 C3 Total R1 10.50 8.00 8.50 27 R2 10.50 8.00 8.50 27 Total 21 16 17 54Related Questions
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