Refer to Question #1 on the Lab3 pdf b. Find the P-value . Due to the different
ID: 3313419 • Letter: R
Question
Refer to Question #1 on the Lab3 pdf
b. Find the P-value. Due to the different methods, select the best possible answer. [ Select ] ["0.0511", "0.2517", "0.0001", "0.1741"]
c. Give the conclusion in context. [ Select ] ["Fail to reject Ho. The sample data provide insufficient evidence to support that women are more likely then men to suffer from arthritis.", "Fail to reject Ho. The sample data provide sufficient evidence to support that women are more likely then men to suffer from arthritis.", "Reject Ho. The sample data provide sufficient evidence to support that women are more likely then men to suffer from arthritis.", "Reject Ho. The sample data provide insufficient evidence to support that women are more likely then men to suffer from arthritis."]
Explanation / Answer
Given that,
sample one, x1 =535, n1 =1068, p1= x1/n1=0.501
sample two, x2 =421, n2 =1012, p2= x2/n2=0.416
null, Ho: p1 = p2
alternate, H1: p1 > p2
level of significance, = 0.1
from standard normal table,right tailed z /2 =1.282
since our test is right-tailed
reject Ho, if zo > 1.282
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.501-0.416)/sqrt((0.46*0.54(1/1068+1/1012))
zo =3.885
| zo | =3.885
critical value
the value of |z | at los 0.1% is 1.282
we got |zo| =3.885 & | z | =1.282
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail - Ha : ( p > 3.8846 ) = 0.00005
hence value of p0.1 > 0.00005,here we reject Ho
ANSWERS
---------------
null, Ho: p1 = p2
alternate, H1: p1 > p2
test statistic: 3.885
critical value: 1.282
decision: reject Ho
p-value: 0.00005
evidence that women are more likely to suffer from arthritis then men
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