Use the folowlng Infarmation to answer qutions (7)- Suppose that the mean Syutol

Question

Use the folowlng Infarmation to answer qutions (7)- Suppose that the mean Syutole blood pressure for adults age so-54·125 mmHg with "tandard deviation of mmkg t Inows that Systolic bleod pressure is net omaly dstributed Suppase a samgle of 25 adut ystolic bleod pressure measurements is taken from the population. . Whatb the approximate standand enrer for the sampling istrbuties of meen blioed pressures? Show your & What is the approximate probablity with interpretation that the average dissiolic blood peesure wll be ess thas 122 mnHg. gven the above information? Raund to the nearest thousandth a. The prebabnyfor ·3.00eriess is less than or eq.. to 3 standard drvations which The prehablity for 3.00 or less is less than or equal to 3 standard deviations which is a signifiean rewit, uung an approuamatono! OS of 11-99.7%)·0.0015 ty for a-3.00 or less is less than or equal to 3 standard deviatons which is a signficant rest, using an aeronason ot 211-99.7%,-00060

Explanation / Answer

7.
mean = 125 mm/hg
stanadard deviation = 5 mm/hg
sample size = 25
stanadard error = sd/ sqrt(n)
where,
sd = population standard deviation
n = population size
stanadard error = ( 5/ sqrt ( 25) )
= 1
8.
Given that,
population mean(u)=122
standard deviation, =5
sample mean, x =125
number (n)=25
null, Ho: <=122
alternate, H1: >122
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.645
since our test is right-tailed
reject Ho, if zo > 1.645
we use test statistic (z) = x-u/(s.d/sqrt(n))
zo = 125-122/(5/sqrt(25)
zo = 3
| zo | = 3
critical value
the value of |z | at los 5% is 1.645
we got |zo| =3 & | z | = 1.645
make decision
hence value of | zo | > | z | and here we reject Ho
p-value : right tail - ha : ( p > 3 ) = 0.00135
hence value of p0.05 > 0.00135, here we reject Ho
ANSWERS
---------------
null, Ho: <=122
alternate, H1: >122
test statistic: 3
critical value: 1.645
decision: reject Ho
p-value: 0.00135

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