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Posted this before and it was answered incorrectly PLEASE ONLY ATTEMPT IF YOU KNOW HOW TO ANSWER THIS QUESTION

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Question 11 Your answer is CORRECT. Data for gas mileage (in mpg) for different vehicles was entered into a software package and part of the ANOVA table is shown below: Source DF SSMS ehicle 6 520 260.00 84 210 2.50 Total 90 730 Determine the value of w needed to apply Tukey's procedure for the distance allowed between means at the 5%significance level a) O4.3 b) 1.9 c) 0.4 d) O 3.4 e) 104.0

Explanation / Answer

here a=6+1 =7 and N-a=91-7=84

for above (6,84) degree of freeedom crtiical q =4.2719

threfore w =q*(MSE/n)1/2 where MSE =2.5 and n=(90+1)/(6+1)=13

w= 4.2719*(2.5/13)1/2 =1.9

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