A recent study of 2400 children randomly selected found 23% of them deficient in

Question

A recent study of 2400 children randomly selected found 23% of them deficient in vitamin D. a) Construct the 98% confidence interval for the true proportion of children who are deficient in vitamin D. Round to three decimal places as needed.) b) Explain carefully what the interval means A we are 90% confident that the interval contains the true proportion of children deficient in vitamin D. B. We are 98% confident that the percent of people deficient in vitamin D C. We are 98% confident that the interval contains the true proportion of people deficient in vitamin D is 23%, 0 D. We are 98% confident that the percent of children deficient in vitamin D is 23% c) Explain what "98% confidence" means About 98% of random samples of size 2400 will produce | that contain the I of children that are deficient in vitamin Click to select your answer(s) vpe here to search

Explanation / Answer

Ans:

a)Confidence interval for true proportion

=0.23+/-2.33*sqrt(0.23*(1-0.23)/2400)

=0.23+/-0.020

=(0.210,0.250)

b)

Option A is correct.

c)

98% confidence interval means that if we take number of sample of size 2400,it will produce limits that contain the true proportion of childeren that are deficient in Vitamin D.

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