An article gave a scatter plot, along with the least squares line, of x - rainfa

Question

An article gave a scatter plot, along with the least squares line, of x - rainfall volume (m3) and y runoff volume (m3) for a particular location. The simple linear regression model provides a very good fit to data on rainfall and runoff volume (n- 15) given below. The equation of the least squares line is y =-0.756 + 0.82248x, r2-0.974, and s = 5.30. x5 12 14 17 23 30 40 47 55 67 72 81 96 112 127 y4 11 14 16 15 24 26 47 39 45 54 69 82 98 101 (a) Use the fact that s 1.45 when rainfall volume is 40 m3 to predict runoff in a way that conveys information about reliability and precision. (Calculate a 95% P. Round your answers to two decimal places.) Does the resulting interval suggest that precise information about the value of runoff for this future observation is available? Explain your reasoning is available because the resulting interval is very wide. O Yes, precise information is available because the resulting interval is very narrow. No, precise information is not available because the resulting interval is very wide No, precise information is not available because the resulting interval is very narrow. (b) Calculate a 95% PI for runoff when rainfall is 50. (Round your answers to two decimal places.) What can be said about the simultaneous prediction level for the two intervals youave calated? The simultaneous prediction levefor the intervals is at least

Explanation / Answer

a) The 95% prediction Interval is (20.26, 44.02)

Correct ansing : Option (C) No,

b) The 95% prediction Interval is  (28.53, 52.20)

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