(a) Reject H 0 because 211.5 is less than 212. (b) Reject H 0 because 211.5 lies
ID: 3314442 • Letter: #
Question
(a) Reject H0 because 211.5 is less than 212. (b) Reject H0 because 211.5 lies in the rejection region. (c) Reject H0 because 2.773 < 2.624. (d) Do not reject H0 because the sample is small. (e) Do not reject H0 because 2.624 > 2.773.
28. In a test of hypotheses H0 : p = 0.81 vs. Ha : p < 0.81 a sample of size 1439 produced the test statistic z = 1.014. The p-value (the observed significance) of the test is about:
(a) 0.81 (b) 0.31 (c) 0.16 (d) 0.16 (e) 1.01
29. A retail chain wishes to test whether accepting additional forms of payments will increase mean weekly sales against the default that it will have no effect. The mean weekly sales at 35 stores at which the new payment options are implemented are compared to the mean sales at the same stores previously. The setup of the null and alternative hypotheses for this test must be:
30. A study investigating the relationship between a child’s age x in years and expressive vocabulary y in words used yielded r = 0.99, s = 132.9, and the regression equation ˆy = 770x 1370. For each additional year in age a child’s expressive vocabulary
(a) increases by about 770 words, on average (b) increases by about 1370 words, on average (c) increases by about 133 words, on average (d) increases by about 938 words, on average (e) changes by an amount that cannot be determined from the information given
Explanation / Answer
27. Reject H0 because 2.773 < 2.624
Option C is correct.
28. p - Value = P(z < -1.014) = 0.16
Option C is correct.
29. H0 : µd = 0 vs. Ha : µd > 0
Option E is correct.
30. increases by about 770 words, on average
Option A is correct.
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