submissions renaring for each question part oly changes f you sutito Assignment

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submissions renaring for each question part oly changes f you sutito Assignment Scoing and 4 numeric columns of cata. The data is frem measurements on core from petroleum cove samplejcross section permeablity, total rocksarea. Assume the area colume of rock is the outcome of a random sample of siee 48 hom a pepulation with dstritution X res of pores, total perimeter of pares, and shape. The data in the area column of rock is the data is the data we shall consider Let the random veriable X n K represent a random observation from ation " Answer the flowing using R K. Assume x nas mea, Md standad the R code to assign the data o the rocksares column te b) Cakalate the range of (Sing-nuntw, c3 using t?e quarese f notion cakulate the 25th percense of x. d) Calulate the sample mean of x Cal this mean xr e) Calouilate the sample medun of f) Calculate the Mmple Mandard deviaton·s, of K. g) Cakulate the omtal value to be used to predvce 97% con droe nterval for " h),ind the lower bondey Or a 97% eontoence intev." " i) rind upper boundary fura ,7% conno-centerval " j) How kng is the 97% cennance nterva. tw k) Copy yor R script for the above into the text bohre

Explanation / Answer

(a) x = rock$area

(b) code: range(x)

use: max(x) – min(x) = 11196

c) For calculating 25th parcentile, quantile(x, .25)

result: 5305.25

d) code: xbar = mean(x)

result: 7187.729

e) median(x) : 7487

f) sd(x): 2683.849

g) The critical value used to create a 97% Confidence Interval of the sample mean is: qt(.985,47)

The output is: 2.237974

h) 97% confidence interval of µ we use: t.test(x,conf.level=.97) = 6320.782

i) Use: t.test(x,conf.level=.97) ,the lower boundary of the 97% confidence interval of µ: 8054.676

j) 8054.676-6320.782=1733.894

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