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dit View History Bookmarks People Window Help 990 a Secure https/www.mathxl.com/Student/PlayerTest.aspxctestid1 Take a Test Tosura K t.aspxttestid 17352694 38centerwineyes BMAL311 C90 Business Statistios Test:Midterm 2 Time Remainings 02:32-28 Su This Question: 6 pts 70, 35(5complete) This Test: 300 pts Corstruct a99% orldere e interval to estimate the population proportion with a sampleproportin oqual to o eo and sample size equal to to view a portion of the Cumulative Probabilities for the Standand Nomal Distribution table % corthdence on aval est ateseded" population proportionisbetween a lowerintof proportion is between a lower limit ofCdanupper int of d an upper into, (Round to three decimal places as needed.) Enter your answer in each of the answer boxes es can be taken for practice or to build your study p not affect your grade. 3 MacBook Air

Explanation / Answer

Step 1: Find /2
Level of Confidence = 95%
= 100% - (Level of Confidence) = 5%
/2 = 2.5% = 0.025

Step 2: Find z/2
Calculate z/2 by using standard normal distribution (normal population with mean () = 0 and standard deviation () = 1)
with /2 = 0.025 as right-tailed area and left-tailed area.

Step 3: Calculate Confidence Interval

z/2 = 1.9599639861

Lower Bound = p - z/2•p(1 - p)/n = 0.6 - (1.9599)(0.02828) = 0.5445

Upper Bound = p + z/2•p(1 - p)/n = 0.6 + (1.9599)(0.0282) = 0.6554

Confidence Interval = (0.5445, 0.6554)

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