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Take a Test-Kailey Miller-Google Chrome Secure : httpc//www.matho.com/Student/Player spx?testld:1669791 STA2023 FALL 2017 ONLINE (CRN 11765) Submit Test Test: Practice Test 3 4 of 23 (2 This Test: 87 pts possibl This Question: 5 pts Overview, question 4 of 2 A physiclan wants to develop citeria for determining whether a patient's pulse rate is atypical, and she wants to determine whether there are significant differences between males and Sernales. Use the sample puse rates below 84 76 72 T6 e 2 60 88 96 76 104 88 124 Female a.Constud a 95%conidence inervalestinaté ofthe mean pulse rate males nd to one decimal place as needed) b.Constud a95% contónce merval estimate ofthe mean pulse rate lor lenale. (Round he ondeanal place as rmoed ) maies and lemales are dterent) resuts Can we conclude that the population means A No because the two corfidence i B. Yes the population r mervals overlep we cannot canclude that the two populatsion means are different ean for females appears to be greater than the popelation mean for males o sesedt yo ovo / 4.ye '. /L,-JEJJu-j ieje -... ..12 rwetExplanation / Answer
Solution:- Given that n = 10 , df = n-1 = 9 t = 2.262
men : 96,84,72,72,76,76,72,68,76,56 => mean = 74.8 , sd = 10.3366
female : 72,76,88,60,88,96,76,104,88,124 => mean = 87.2 , sd = 18.0665
a) 95% confidence interval estimate of the mean pulse rate for males:
=> X +/- t * sd/sqrt(n)
= 74.8 +/- 2.262*(10.3366/sqrt(10))
= ( 67.4062 , 82.1938)
= ( 67.4 , 82.2) rounded
b)
95% confidence interval estimate of the mean pulse rate for females:
=> X +/- t * sd/sqrt(n)
= 87.2 +/- 2.262*(18.0665/sqrt(10))
= (74.2769 , 100.123)
= ( 74.3 , 100.1) rounded
c. Yes, because the two confidence intervals do not overlap, we can conclude that the two population means are different.
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