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P Do Homework - Paige Maroney - Google Chrome Secure ! https://www.mathxl.com/Student/PlayerHomework.aspx?homeworkid=441 1 57146&questionid;=7&flushed;=false&cid;=4624428¢er; in.. Q MAT 120 82 FA17 Daniels Paige Maroney | 12/4/17 12:46 PM work: Section 7.2 Homework Home Save Score: 0 of 1 pt 7 of 9 (9 complete) HW Score: 88.89%, 8 of 9 pts X7.2.27-E Question Help Refer to the accompanying data set of mean drive-through service times at dinner in seconds at two fast food restaurants. Construct a 95% confidence interval estimate of the mean drive-through service time for Restaurant X at dinner, then do the same for Restaurant Y. Compare the results E Click the icon to view the data on drive-through service times Construct a 95% confidence interval of the Restaurant Drive-Through Service Times (Round to one decimal place as needed.) Service Times (seconds) Restaurant X Restaurant Y 85 122 118 146 262 98 125 155 120 172 177 122 150 160 208 137 114 120 129 128 329 305 174 111 160 130 140 230 211 290 145 99 236 238 181 128 98134 247 148 154 199 166 121 63 147 204 148 140 142 204 180 117 138 177 148 152 130 167 136 189 200 236 197 354 238 236 248 233 237 307 210 194 184 189 168 8210 59167 101 148 175 157 169 74 143 138 99 127 153 161 124 140 313 148 128 182 148 129 Enter vour answer in the edit fields and t parts remainingExplanation / Answer
Mean of X = 178.96
Standard deviation of X = 63
n = 50
Standard error of the mean = SD / sqrt(n) = 63 / sqrt(50) = 8.91
Z value for 95% confidence interval is 1.96
95% confidence interval of mean of service time at restaurant X is,
(178.96 - 1.96 * 8.91, 178.96 + 1.96 * 8.91)
(161.5 , 196.4)
Mean of Y = 153.06
Standard deviation of Y = 49.65
n = 50
Standard error of the mean = SD / sqrt(n) = 49.65 / sqrt(50) = 7.02
Z value for 95% confidence interval is 1.96
95% confidence interval of mean of service time at restaurant X is,
(153.06 - 1.96 * 7.02, 153.06 + 1.96 * 7.02)
(139.3 , 166.8)
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