2150-656 x: gC What is the equation ofthe line of best fit? y=a+bx y=y: 3-1x If
ID: 3316911 • Letter: 2
Question
2150-656 x: gC What is the equation ofthe line of best fit? y=a+bx y=y: 3-1x If the independent variable is-2, predict for = 3-12) 3. The average yearly earnings of female college graduates with the same qualification are 3-2-C $50,000. Based on the results below, can it be concluded that there is a difference in mean earnings between male and female college graduates? Use the 0,.01level of significance. Sample means Population standard deviation Sample size $59,200 8,900 S 52,400 10,100 35 40 I1) State the hypotheses and identify the claim. Ho: Hi 2) Find the critical value. CV 3) Compute the test value. Test-value 1- 2-L- ni n2 4) Make the decision and summarize the result Have a nice week Page 2Explanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: 1 - 2 = 0
Alternative hypothesis: 1 - 2 0
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the difference between sample means is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.01. Using sample data, we will conduct a two-sample t-test of the null hypothesis.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = sqrt[(s12/n1) + (s22/n2)]
SE = 2212.42
DF = 73
t = [ (x1 - x2) - d ] / SE
t = 3.07
tcritical = 2.89
Rejection region t > 2.89
where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is the size of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between the population means, and SE is the standard error.
Since we have a two-tailed test, the P-value is the probability that a t statistic having 73 degrees of freedom is more extreme than -3.07; that is, less than -3.07 or greater than 3.07.
Thus, the P-value = 0.0030
Interpret results. Since the P-value (0.0030) is less than the significance level (0.01), we have to accept the null hypothesis.
From the above test we have sufficient evidence in the favor of the claim that there is difference in the mean earnings of male and females.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.