The author drilled a hole in a die and filled it with a lead weight, then procee

Question

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 209 times. Here are the observed frequencies for the outcomes of 1,2,3,4,5, and 6 respectively: 18, 38, 44, 47, 26, 36. Use a 0.05 significance level to test the claim that the outcomes are not equally likely. Does it appear that the loaded die behaves differently than a fair die? Does it appear that the loaded die behaves differently than a regular die? O A. d B. ° C. No, because the test statistic is greater than the critical value. Yes, because the test statistic is less than or equal to the critical value. No, because the test statistic is less than or equal to the critical value. D. Yes, because the test statistic is greater than the critical value

Explanation / Answer

Ans:

Chi square test statistic=17.364

df=6-1=5

critical chi square=CHIINV(0.05,5)=11.071

As,observed test statistic=17.364>11.071,we reject null hypothesis.

There is sufficient evidence that loaded die behaves significantly different than a regular die.

So,the correct answer is option D.

Yes,because the test statistic is greater than the critical value.

Observed(O) Expected(E) (O-E)^2/E 1 18 34.83 8.13 2 38 34.83 0.29 3 44 34.83 2.41 4 47 34.83 4.25 5 26 34.83 2.24 6 36 34.83 0.04 Total 209 209 17.364

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