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i safari File Edit View History Bookmarks Window Help 63% Ct} Wed 4:36 PM a Plea

ID: 3317523 • Letter: I

Question

i safari File Edit View History Bookmarks Window Help 63% Ct} Wed 4:36 PM a Please Help Me Thanks!! Connect Chapter 10 G Saved Help Save & Exit Submit 41 PM Check my work 4 The mean income per person in the United States is $41,000, and the distribution of incomes follows a normal distribution. A random sample of 9 residents of Wilmington, Delaware, had a mean of $51,000 with a standard deviation of $10,400. At the 0.025 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average? een Shot 12..17.44 PM points a. State the null hypothesis and the alternate hypothesis. een Shot 12...20.32 PM eBook Print H0: H1: > een Shot 12...0.38 PM b. State the decision rule for 0.025 significance level. (Round your answer to 3 decimal places.) cen Shot 2...22.25 PM HO if t> een Shot 2...22.27 PM c. Compute the value of the test statistic. (Round your answer to 2 decimal places.) the een Shot 12...4.44 PM 6

Explanation / Answer

The statistical software output for this problem is:

One sample T summary hypothesis test:
: Mean of population
H0 : = 41000
HA : > 41000

Hypothesis test results:

Hence,

a) Hypotheses:

H0 : < 41000
H1 : > 41000

b) Reject Ho if t > 2.306

c) Test statistic = 2.88

d) Reject; sufficient; higher than (more than)

Mean Sample Mean Std. Err. DF T-Stat P-value 51000 3466.6667 8 2.8846154 0.0102