19. Absentee rates Friday vs Wednesday: We want to test whether or not more stud

Question

19. Absentee rates Friday vs Wednesday: We want to test whether or not more students are absent on Friday afternoon classes than on Wednesday afternoon classes. In a random sample of 302 students with Friday afternoon dlasses, 48 missed the class. In a different random sample of 307 students with Wednesday afternoon dasses, 32 missed the cdass. The table below summarizes this information. The standard error (SE) is given to save calculation time if you are not using software Data Summary total number total number Proportion Day of absences (x) of students (n) p (xin Friday48 302 307 0.15894 0.10-423 Wednesday32 SE 0.02 738 Test the daim that the ab tee rate on all Friday afternoon classes is greater than the absentee rate on all wednesday a er oondasses. Use ao. significance level absentee rate from the sample on Friday and be the rate from wednesday, calculate the test statistic using software or the formula (a) Letting be the where S, lIs the hypothesized difference in proportions from the null hypothesis and the standard error (SE) given with the data. Round your answer to 2 decimal places. To account for hand calculations -ws- software, your answer must be within o.01 of the true answer (b) Use software or the z-table to get the P-value of the test statistic Round to 4 decimal places. p-value (c) What is the conclusion regarding the null hypothesis? O reject Ho fail to reject H (d) Choose the appropriate concluding statement O The data supports the claim that the absentee rate on all Friday afternoon classes is greater than the absentee rate on all Wednesday afternoon classes. than the absentee rate on all wednesday O There is not enough data to support the claim that the absentee rate on all Friday afternoon classes is greater afternoon classes 0 we have proven that the absentee rate on all Friday afternoon classes is greater than the absentee rate on all wednesday afternoon classes 0 we reject the claim that the absentee rate on an Friday afternoon classes is greater than the absentee rate on all wednesday afternoon classes. Additional Materials

Explanation / Answer

Ans:

a)

z=(0.15894-0.10423)/0.02738=2

b)p-value=P(z>2)=0.0228

c)As,p-value>0.01,we fail to reject H0.

d)There is not enough evidence to support the claim that the absecnce rate on all friday afternoon classes is greater than the absence rate on all wednesday afternoon classes

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.