Dr. Mindfog, is a drug researcher interested in investigating the mind-altering

Question

Dr. Mindfog, is a drug researcher interested in investigating the mind-altering effects of two very potent drugs, scotch and tequila. Specifically, Dr. Mindfog wonders, “Is there a difference between the two drugs in their mind-altering effects?” Wishing to minimize and effects due to physical differences in groups of subjects, he selects ten adult twin pairs to participate in his study (five mail twin pairs and five female twin pairs, obviously matched). One member of each twin pair is randomly assigned to one of two groups, such that one member of a twin pair is in the “scotch” group and the other member of the twin pair is in the “tequila” group. Then, using the famous Olson Mind Dazedness Test (OMDT) he measures each participant’s dazedness after self-administering three ounces of the drug within an hour’s time. Below are the dazedness scores of Dr. Mindfog’s experiment -- the higher the score, the more dazed the participant.

Group 1

Scotch

Dazedness Scores

Group 2

Tequila

Complete step 3 of the hypothesis testing procedure and calculate the appropriate z , t, or r. Round to the nearest hundredths place. If your calculated z , t, or r is not identical to one of the values below, but within plus or minus 0.16 of an answer below, assume it's a rounding error and select the answer that is closest to your calculated value. Ignore the minus sign if your calculated z or t is negative, but if you calculate r and it's negative, of course, write the minus sign.

E. 2.89

F. Not listed

Twin Pairs

Group 1

Scotch

Dazedness Scores

Group 2

Tequila

Dazedness Scores Bob & Bubba 7 9 Fred & Frank 4 4 Tim & Tom 6 5 Mary & Madeline 5 8 Elvira & Evelyn 4 3 Juan & Jaime 4 8 Charla & Carla 9 10 Jim & John 8 9 Cindy & Sandy 5 8 Margaret & Marlene 3 4

Explanation / Answer

HEre first thing is to identof which test we shall employ in the given test . Here as it seems that it may be a paired t test. But, itis just to create the confusion only. Here the paired are made only by random selection and even by it is divided into two groups by randomselection.

SO we will use t - test for equal variances not the paired t test here.

HEre the sample mean and variance are given here.

So,  

Pooled standard deviation sp = sqrt [ (3.83 + 6.4)/2]= 5.1167

Here test statitstic

t = (x1 - x2)/sp * sqrt(1/n1 + 1/n2) ]

t = (5.5 - 6.8/ sqrt[5.1167 * (1/10 + 1/10)]

t = (-1.3)// 1.0116 = -1.2851

so here the answer is option b here.  t = 1.29

Group 1 Group 2 Mean 5.5 6.8 Variance 3.83 6.4 Observations 10 10

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