2017Fall-2332-Final-Ver-12-5-Word ACROBAT Tell me what you want to do · T1Normal

Question

2017Fall-2332-Final-Ver-12-5-Word ACROBAT Tell me what you want to do · T1Normal!No Spac.. Heading 1 Headng2 Title Subtitle Subtle Em. Emphasis Intense E.. Styles MATH 2332-FALL 2017 Write the answers, including the work, on the Answer Sheet Provided by the Instructor Problem 1(13pts) A student is studying for the test which has 36 questions. Each question is a multiple choice question with 6 options. The student studied 66.66% of the content of the test. The rest of the test he will randomly pick the answer. We assume that students answered correctly al the questions he or she studied. (A) (1pt) Find P(Score=5). (B) (2pts) Find P(Score= 30). (C) (2pts) Find P(Score= k). (D) (3pts) What should the student expect to be his score on the test? (E) (2pts) Another student scored 28 on the test. What is the expected value of the material the student studied? (F) (3pts) 100 students took the test. The average test score was 32 with standard deviation of 9, Find 95% confidence interval for the amount of material (in percentage) the students studied? Problem 2. (2pts) A sanitary inspection visit 5 restaurants on 10 different occasions. It graded them on the scale 0-100. A company is using these scores to determine whether any of the restaurants need to improve. Which tool you would suggest to the company to see whether there is any difference between the sanitary score of the five restaurants? a) Confidence intervals b) ANOVA c) Correlation Matrix d) Linear Regression e) Histograms f) CATNAP Problem 3. (2pts) yewould like to use SAT scores to predict students success in their first Math Course, which tool should we use? a) Confidence intervals b) ANOVA Correlation Matrix

Explanation / Answer

Hello,

Since you are having a problem with question 1, part D and E as you have underlined it I'll try to explain it to you in a very lucid manner.

D)Now for the first case,

The student studied 66.66% of the questions from the 36 questions and the rest of them he will just randomise.

Therefore if there are 36 questions provided he knows 66.66% of the questions, he knows 23.9974 questions that is roughly 24 questions. Now, since each MCQ has 6 options, the student has a probability to answer correctly of 1/6. Therefore amongst the (36-24) questions left, i.e, amongst the 12 questions he will expect to answer 12*1/6 questions correctly, i.e.,2. Therefore on a total he can expect to answer 24+2 questions, i.e, 26 questions.

E) Now if a student answers 28 questions, then 28/36 = 0.7777.

Therefore the expected value of the material that the student studied is 77.7777%.

Hope it helped. Cheers!

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.