50. Atakmized black deep, wi 4 treatmen without retas and 5 tapdal treatmests mu

Question

50. Atakmized black deep, wi 4 treatmen without retas and 5 tapdal treatmests mus be A) 16 51. Given the leass squares gression line -4.63+138, and a comelatios ef deteramination of 0.90, he coefficient desermination most be A) 095 -0.9 52. In a regression model ievolving 40 observations, the following etimased nepessicn 6 C) +1.38 A)0.198 B)0.05 C)1.00 D)167 SX in a chi-square gpodnem-of-fit test with 5 degrees of freedom and a significance level of cost test statistc wll lead to rejection of the null hypothesis? E0914 the table is 11070S Which of the tullowing compubed values of the ehi-square A) 8952 B) 78146814 D. 1761 E025 con was tossed 250tines, and heads wasobsened 54, TO determine wwthe.coin isfar, 140 times. The valun ofthe test stoetatic 0) A) 36 B) 140 Whm you hased a coin fon mper mark " and found there were 315seeds showed puple and ss. t5 deed iss.mbéowed nd s-w, 135 sends showed yellow and noe-oweet,.nd Assortmen 9P-3P-usuc 3pp51.pu 1 at Xa 0.% What are the vale of Xand conusi AX, 1.27.dthedeout-the deck law cr maperdent Aisorment pPS.:1psa )X5.327 and the dts are fiand the Genetic law of Independent Assortment (9P-u: 3P-susu C) X17 mdthe dram schatte Geneticia.of ndependenAsartment (9aegau

Explanation / Answer

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52) SSR = 501

SSE = 99

SST = 501 + 99 = 600

R^2 = SSR/SST

R^2 = 501/600

R^2 = 0.835

B option

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