20. /4 points DevoreStat9 8.E.022 My Notes Ask Your Teacher To obtain informatio
ID: 3318756 • Letter: 2
Question
20. /4 points DevoreStat9 8.E.022 My Notes Ask Your Teacher To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x = 52.5 and a sample standard deviation of s = 4.7. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that the specification has not been met. what would you conclude? (Use = 0.05.) State the appropriate null and alternative hypotheses H0: = 50 Ha: > 50 Ha: > 50 Ha: # 50 Ha: = 50 Ho: = 50 Ho: > 50 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) P-value- State the conclusion in the problem context. Reject the null hypothesis. There is sufficient evidence to conclude that the true average penetration is more than 50 mils Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average penetration is more Reject the null hypothesis. There is not sufficient evidence to conclude that the true average penetration is more than Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true average penetration is than 50 mils 50 mils more than 50 mils You may need to use the appropriate table in the Appendix of Tables to answer this questionExplanation / Answer
The statistical software output for this problem is:
One sample T summary hypothesis test:
: Mean of population
H0 : = 50
HA : > 50
Hypothesis test results:
Hence,
Hypotheses: Option A is correct.
z = 3.57
P - value = 0.004
Conclusion: Option A is correct.
Mean Sample Mean Std. Err. DF T-Stat P-value 52.5 0.70063463 44 3.5681936 0.0004Related Questions
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