The claim is that the proportion of adults who smoked a cigarette in the past we

Question

The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.25, and the sample statistics include n 1926 subjects with 443 saying that they smoked a cigarette in the past week. Find the value of the test statistic. The test statistic is (Round to two decimal places as needed.) Using a table of critical t-values of the t distribution, find the range of values for the P-value for testing a claim about the mean body temperature of healthy adults for a left-tailed test with n 13 and test statistic t-2.017 Click the icon to view a table of critical t-values. What is the range of values for the P-value? OA. P-value 0.005 OB, 0.025

Explanation / Answer

A) P = 0.25

p = 443 / 1926 = 0.23

Sigma = sqrt (P *(1-P)/n) = sqrt(0.25 * 0.75 / 1926) = 0.0097

Test statistic = (p - P) /sigma = (0.23 - 0.25) / 0.0097 = - 2.06

B) t = - 2.017

t0.05 < t < t0.025

Or, 0.025 < P-value < 0.05

Option-B) 0.025 < P-value < 0.05

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