What is the conclusion about the null hypothesis?_______ A. Rejectthe null hypot
ID: 3318916 • Letter: W
Question
What is the conclusion about the null hypothesis?_______
A. Rejectthe null hypothesis because the P-value is less than or equal tothe significance level,alpha.
B. Fail to reject the null hypothesis because the P-value is greater than the significance level,alpha.
C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, alpha.
D. Reject the null hypothesis because the P-value is greater than the significance level, alpha.
What is the final conclusion?_______
A.There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
B. There is sufficient evidence to support the claim that less than 27 of offspring peas will be yellow.
C. There is not sufficient evidence to support the claim that less than 27 of offspring peas will be yellow.
D.There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 421 green peas and 120 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P.value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? OA. Ho: p=0.27 OB. He: p=0.27 Hy: p0.27 OF. Ho: p#0.27 O E. Ho: p#0.27 Hy: p0.27 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P.value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. Click to select your answer(s).Explanation / Answer
Solution:
A genetic experiment involving peas yielded one sample of offspring consisting of 421 green peas and 120 yellow peas.
The claim is that 27% of offspring peas will be yellow.
The null and alternative hypotheses are,
A. H0: p = 0.27
H1: p 0.27
The proportion of yellow peas in sample is,
p = X/n = 120/421+ 120 = 0.222
The test statistic is obtained using normal distribution as an approximation to the binomial distribution is as follows:
Z = p - p /sqrt[p(1-p)/n]
= 0.222- 0.27/sqrt[0.27(1-0.27)/421]
= -2.22
The value of test statistic is -2.22.
P-value = 0.0264
The probability value of the test statistic is 0.0264. Since 0.0264 < 0.05 the null hypothesis is rejected at 95% level of significance.
Reject the null hypothesis.
There is sufficient no evidence to support the claim that under the given circumstances 27% of offspring peas will be yellow.
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