raditiona 273 53.9 28.5 21.4, 30. )Statistical training. The accounting firm des
ID: 3319976 • Letter: R
Question
raditiona 273 53.9 28.5 21.4, 30. )Statistical training. The accounting firm describe 8.5, 10 se 28 is interested in providing opportunities for a) Wrire its auditors to gain more expertise in statistical sampling b) Check methods. They wish to compare traditional classroom in- c) Find t struction with online self-paced tutorials. Auditors were means. assigned at random to one type of instruction, and the au- d) Is the ditors were then given an exam. The table shows how the betwee two groups performed. What do you conclude? (Assume the assumptions for inference are met.) 34.) itali Italian pH (a Program n Mean SD Traditional29674.5 11.2 Online 275 72.9 12.3Explanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: 1 = 2
Alternative hypothesis: 1 2
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the difference between sample means is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a two-sample t-test of the null hypothesis.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = sqrt[(s12/n1) + (s22/n2)]
SE = 0.987
DF = 569
t = [ (x1 - x2) - d ] / SE
t = 1.62
where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is the size of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between the population means, and SE is the standard error.
Since we have a two-tailed test, the P-value is the probability that a t statistic having 569 degrees of freedom is more extreme than -1.62; that is, less than -1.62 or greater than 1.62.
Thus, the P-value = 0.1052.
Interpret results. Since the P-value (0.1052) is greater than the significance level (0.05), we cannot accept the null hypothesis.
Hence we have sufficient evidence that mean of two programs are same.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.