In size-n random sampling from a bivariate population f(x, y), suppose that the
ID: 3320328 • Letter: I
Question
In size-n random sampling from a bivariate population f(x, y), suppose that the objective is to estimate the parameter Ax For example, the population may consist of married couples, with Y = husband's earnings and X - wife's earnings. The sample statistics X, Y, s2, s , and SXY are available. (a) Propose a statistic T that is an unbiased estimator of . Show that it is unbiased. (b) Find its variance V(T) in terms of the population variances and covariance of X and Y. (c) For the practical case, in which those population variances and covariance are unknown, propose an unbiased estimator of V(T). Show that it is unbiased. (d) What statistic would you report in practice as a standard erroir for T?Explanation / Answer
Part (a)
Given = µY - µX, let T = Ybar – Xbar. Then T is an unbiased estimator of . ANSWER
Proof: E(T) = E(Ybar – Xbar) = E(Ybar) – E(Xbar) = µY - µX.
=> (Ybar – Xbar) is an unbiased estimator of . DONE
Part (b)
V(T) = V(Ybar – Xbar) = V(Ybar) + V(Xbar) – 2Cov(Ybar, Xbar) = (1/n)(12 + 22 - 212),
Where 12 , 22 and 12 are respectively variance of X, Y and Cov(X, Y).
Thus, V(T) = (12 + 22 - 212)/n ANSWER
Part (c)
E{(n - 1)SX2} = 12 , E{(n - 1)SY2} = 22 , and E{(n - 1)SXY} = 12 . So,
E[(n - 1)(SX2 + SY2 - 2SXY)] = (12 + 22 - 212)
=> E[{(n - 1)/n}(SX2 + SY2 - 2SXY)] = (12 + 22 - 2 12)/n
=> [{(n - 1)/n}(SX2 + SY2 - 2SXY)] is an unbiased estimator of V(T) ANSWER
Part (d)
From Part (b), V(T) = (1/n)(12 + 22 - 2 12)
=> SE(T) = sqrt{(1/n)(12 + 22 - 212)} ANSWER
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.