©2017 daabz.com Statisties Quiz 9 version 1 page 2 of 6 Statistics Quiz 9 versio

Question

©2017 daabz.com Statisties Quiz 9 version 1 page 2 of 6 Statistics Quiz 9 version 1 (page 3/ 6) 9-The paired data below consist ofthe length of random bears in inches and their weight in pounds. Find the value of the linear correlation coefficient T. in 65.0 39.0 32.0 43.0 55.0 454.0 402.0 504.0 A r = 0.8937 B 0.8087 C | 1.1112 D None of these 10. The paired data below consist of the length of random bears in inches and thein weight in pounds. Find and use the correlation equation to predict the weight of a bear that measures 52 inches.

Explanation / Answer

calculation procedure for correlation
sum of (x) = x = 224
sum of (y) = y = 2268
sum of (x^2)= x^2 = 10444
sum of (y^2)= y^2 = 1081400
sum of (x*y)= x*y = 105752
to caluclate value of r( x,y) = covariance ( x,y ) / sd (x) * sd (y)
covariance ( x,y ) = [ x*y - N *(x/N) * (y/N) ]/n-1
= 105752 - [ 5 * (224/5) * (2268/5) ]/5- 1
= 829.12
and now to calculate r( x,y) = 829.12/ (SQRT(1/5*105752-(1/5*224)^2) ) * ( SQRT(1/5*105752-(1/5*2268)^2)
=829.12 / (9.0421*102.6014)
=0.8937
value of correlation is =0.8937

( X) ( Y) X^2 Y^2 X*Y 55 608 3025 369664 33440 39 454 1521 206116 17706 32 300 1024 90000 9600 43 402 1849 161604 17286 55 504 3025 254016 27720

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