11% Dul Sun 6:06 PM a Math43 Fall2017 Liang ha anh tran & 12/10/17 6:06 PM Test:
ID: 3321019 • Letter: 1
Question
11% Dul Sun 6:06 PM a Math43 Fall2017 Liang ha anh tran & 12/10/17 6:06 PM Test: Final 01-20:12 Submit Test This Question: 1 pt This Test: 9 pts 167 169 157 a) Among the 527 human resource professionals who were surveyed, how many of them said that body piercings and tattoos were big grooming red fags? 184 189 (Round to the nearest integer as needed.) 183 b) Construct a 99% confidence interval estimate of the proportion of an h an resource professionals believing 175 flags 205 (Round to three decimal places as needed.) 195) c) Repeat part (b) using a confidence level of 80%. (Round to three decimal places as needed.) d) Compare the confidence intervals from parts (b) and (c) and identify the interval that is wider. Why is it wider? 512 898 Click to select your answerfs) So the p.alues P(t with df=11>2.49-0.015 (from student t table)Explanation / Answer
Answer to the question is as follows:
n = 527
p^ = .429
a. No. of people said that body pericing and tattoos were big grooming red flags = p^ * n = 527*.429 = 226.083 or 226 people
226
b.A 99% CI is given by ?. Z is 2.56 fir 99% CI
p^ +/- Z*sqrt(p^*p^'/n)
=.429 +/- 2.56*sqrt(.429*.571/527)
=.3738 to .4842
.374<p<.484
c. For a 80% confidence the Z is 1.28
p^ +/- Z*sqrt(p^*p^'/n)
=.429 +/- 1.28*sqrt(.429*.571/527)
=.401 to .457
d. The CI in B) is for a higher confidence, and therefore is wider. You can clearly see that in terms of the
ranges of b. and c. Also, the CI is about the population params , and not the sample param.
Hence, the right answer is :
C. The 99% CI is wider than the 80% CI. As the CI widens, the probability that the CI actually does contain the population param increases
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