a) Find the mean time taken to prepare a tax return for the 30 employees from th

Question

a) Find the mean time taken to prepare a tax return for the 30 employees from the grouped frequency distribution. Explain or show how you arrived at your answer. (Use the extra columns in the table if needed.)

b) What is the modal class?

c) What is the median class?

d) Why is the mean you calculated in part a) of this question an estimate?

PLEASE SHOW WORK AND PLEASE DONT PUT ANSWERS IN A PICTURE BECAUSE I CANT OPEN PICS AND SEE THEM FOR SOME REASON

Edit and reply Quiz 3 make-up Accessibility Mode 2. The raw data trom the previous question have been summarized in the tollowing grouped frequency distribution: (18 points) Number of Minutes toNumber of Prepare a Tax Return Employees, f 40-43 44-47 48-51 52-55 56-59 60-63 64-67 2 4 6 4 4

Explanation / Answer

The group or interval which has higest frequency that is denoted as Modal Class . here "52-55" class has highest frequency 6 , so this is the modal class .

Add up all the frequencies 2+3+4+6+4+4+2=25

the median is 0 to 25 , 13

Starting with 00, add the frequencies in the table starting with the first row until you reach 13 The median class interval is the corresponding class where the median value falls.

i.e, 60-63 .(median class )

Here we take mean as best estimator as because this positively skewed distribution , so mean>median & mean is affected due to the change of values .

mean :

for mean take [sum of( Xi*fi)]/[sum of fi] where xi be the class midpoint as eg. 41.5 (ffor 1st group),44.5 (for 2nd group) so on . and fi be the correspondi frequency as 2 (for 1st group) , 3 (for 2nd group) so on .

so neumerator is (41.5*2)+(44.5*3)+............+(65.5*2)=1345.5

denominator is 2+3+......+2 =25

so mean is 53.82

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