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ID: 3321438 • Letter: W
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www-awh.connectmath.com Next Previous 11 12 13 14 15 16 4.1 Section Exercise 32 Question 14 of 16 (1 point) View problem in a pop-up Here are the living arrangements of children under 18 years old living in one country in a recent year. Numbers are in thousands. Both parents 51,911 Mother only 17,07 Father only Neither parent 3,154 2,387 Download data Choose one child at random. Find the following probabilities. Enter your answers as fractions or decimals rounded to 3 decimal places. As Lin Part The child lives with neither parent. P(child lives with neither parent)- 0.042 Sa Subm Part 2 out of 2 The child lives with one parent present. P(child lives with one parent present)-Explanation / Answer
Part 1
p( Child lives with niether parent) = n( niether parent) / n(Total number of child)
= 3154 / (51911 + 17076 + 2387 + 3154)
= 0.042
Part 2
p (Child lives with one parent present) =
[ n( child lives with only mother) + p( Child lives with only father) ] / n(total childs)
= ( 17076 + 2387 ) / (51911 + 17076 + 2387 + 3154)
= 0.261
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