Dgc: 412 Nane o I412 Name /or ID Question 4. (a) (RUMORS FLY WITHOUT WINGS) Assu

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Dgc: 412 Nane o I412 Name /or ID Question 4. (a) (RUMORS FLY WITHOUT WINGS) Assume that it is true that a takes an average of 8 hours with a standard deviation of 2.5 hours to get spread across t whole campus among the students and follows normal distribution College girls make rumors At 5:00pm, while going to home, she wonders what proportion of students will know her due to the rumor? One day at 2:00pm, Amy made a rumor outside the library with a group of girl students. Hint: Use Z-Table. (b) (MEASURES OF CENTER) The sample mean of two numbers is DGc.and the sample variance of the two numbers is!(DGC)2= Find the two numbers. Amy doing math

Explanation / Answer

a) mean = 8 , sd = 2.5
time between 2 pm and 5 pm = 3
P(X < 3) = P(Z < (3 - 8)/2.5)
= P(Z < -2 )
= 0.0228

b) sample mean = 412
sample variance = 1/2 * 412^2
let number are x and y
(x+y)/2 = 412
(x-412)^2 + (y - 412)^2 = 1/2 * 412^2
solving we get
x = 206 , y = 618

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