a. If the subjects are selected and treated in sequence, how many different sequ

Question

a. If the subjects are selected and treated in sequence, how many different sequential arrangements are possible if 5 people are selected from the 8 that are available? A. 120 B. 56 C. 6,720 D. 40,320
b. If 5 subjects are selected from the 8 that are available, and the 5 selected subjects are all treated at the same time, how many different treatment groups are possible?
c. If 5 subjects are randomly selected and treated at the same time, what is the probability of selecting the 5 youngest subjects? A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For example, a phase I test of a specific drug involved only 5 subjects. Assume that we want to treat 5 healthy humans with this new drug and we have 8 suitable volunteers available. Complete parts (a) through (c) below a. If the subjects are selected and treated in sequence, so that the trial is discontinued if anyone displays adverse effects, how many different sequential arrangements are possible if 5 people are selected from the 8 that are available? Choose the correct answer belovw O A. 120 O B. 56 C. 6,720 OD, 40,320 b. If 5 subjects are selected from the 8 that are available, and the 5 selected subjects are all treated at the same time, how many different treatment groups are possible? There are different treatment groups possible. c. If 5 subjects are randomly selected and treated at the same time, what is the probability of selecting the 5 youngest subjects? P(selecting the 5 youngest subjects). (Type an integer or a simplified fraction. )

Explanation / Answer

a) Since there is a sequence to be folllowed hence the order matters. This can be done by permutations

8 P5 ways =8!/(*-5)!=6720 option C

b) Here the order does not matter we have to form group of 5 from 8 people

8C5 ways=8!/5!*(8-5)!=56

c) Out of 8 people there can be only 1 possible way for 5 youngest subject

Hence 1 way

Total number of ways=8C5

Probability=1/8C5=1/56

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