x.P(x) mear.of Preb. Dish;h.: E[Game]. E[win]-Cost exfectevalue: x P(x) Binorial
ID: 3322943 • Letter: X
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x.P(x) mear.of Preb. Dish;h.: E[Game]. E[win]-Cost exfectevalue: x P(x) Binorial Distrib: P(x,x Mean StanQ 6560 and 3 en be women annd' 8 mwa, inadepartment. Now many way an a group of Sconsist of 2 women E) 980 D) 5880 card T Find the indiceted probabilin cands what is the probability that you get nelther a red card nor a face is the 9 1f yeu pick a cand naerndomly from 2 E) D) ) B, 15% of type C. 20% of type A, 30% of type , 40% of % of type A,40% af type ype C have SS0 sold state drive), If a laptop is selected randomly, find probability it has no SsD. 6)Astresell, 3types oflaptopur sells 45 0.976 D) 0.57 E) 0.27 4)a34 There are 7dnno rats, 4 republians, and 3 tndependent voters in a room. If 3 voters are randomly selected. Find the probability that there is at least I independent voter among them. A).99 D) 01 .547 E) 453 Find the indicated probability. 8) The table below describes the smoking habits of a group of asthma sufferers Light Heavy Nonsmoker smoker smoker Total 392 61 2 Total Ia person is randomly selected, find the probability that the person is a nonsmoker given the person is a woman. A) 0-378 B) 0.520 C) 0407 D) 0.747 E) 0.675 9) For tabove problem(#8), find the probability that the person is a woman or Light smoker. A) 059 B).593 C).652 D) 407 E) .116 a player rolls two dice and gets a sum of 9, he wins $ 7. if he gets a double, he wins $ 5. The cost of playing the ga Find the expectation of the game ? :-$1.47 B)-$1.94 C)-$1.39 D)-$1.06 hemy, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. E)-$1.61 ch flavor B)2775 C 0667 D) 1818Explanation / Answer
5) P (red card) = 26/52
P(face cards) = 12/52
P(red and face card) = 6/52
Thus P(neither red nor face card) = P (red card)+ P(face cards)- P(red and face card)
= 26/52 + 12/52 –6/52
= 32/52
= 8/13 (Option A)
6)
P(no SSD) = P(A)*P(no SSD for A) + P(B)*P(no SSD for B) + P(C)*P(no SSD for C)
= 0.45 * (1-0.20) + 0.40 * (1-0.30) + 0.15 * (1-0.40)
= 0.73 (Option B)
7)
Total = 7+4+3 = 14
P(no independent voter) = 11C3/14C3 = 11*10*9/14*13*12 = 0.453
{as removing 3 independent voters rest can be chosen in 11C3 ways while total ways are 14C3}
Thus, P(atleast 1 independent voter) = 1 - P(no independent voter)
= 1-0.453 = 0.547(Option C)
8) P(nonsmoker/women) = 392 / (392+61+72)
= 0.747 (Option D)
9)P(Women or light smoker) = P(Women) + P (light smoker) - P(Women and light smoker)
= (392+61+72) / (392+61+72+362+89+60) + (89+61) /(392+61+72+362+89+60) – 61/(392+61+72+362+89+60)
= 525/1036 + 89/1036
= 0.593 (Option B)
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