According to a Pew Research Center nationwide telephone survey of adults conduct

Question

According to a Pew Research Center nationwide telephone survey of adults conducted March 15 to April 24, 2011, 69% of college graduates said that their college education gave them maturity (Time, May 30, 2011). Suppose that this survey included n = 1465 college graduates. a. What is the point estimate of the corresponding population proportion? b. Construct a 90% confidence interval for the proportion of all college graduates who will say that their college education gave them maturity, what is the margin of error for this estimate? Round your answers to three decimal places. The confidence interval is to The margin of error is E Click if you would like to Show Work for this question: Open Show Work

Explanation / Answer

p is 0.69 and N is 1465

a) p is 0.69

b) z for 90% confidence is 1.65

margin of error ME=z*sqr(p*(1-p)/N)=1.65*sqrt(0.69*0.31/1465)=0.01994

lower bound is p-ME=0.69-0.01994=0.67006

upper bound is p+ME=0.69+0.01994=0.70994

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