5. In a random sample of 16 laptop computers, the mean repair cont was standard

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5. In a random sample of 16 laptop computers, the mean repair cont was standard deviation of S31.50. Which of the following is a 90% population mean repair cost? $120 with a confidence interval for the sample A. (107.05, 132.95) B. (106.19, 133.81) C. (103.22, 136.78) D. None of the above. 6. A survey among adults found that people keep their cell phone an average of 1 55 sa before buying a new one. Assume that the lengths of time people kep their phones are normally distributed with a randomly selected adult will keep his or her cell phone for less than one year before buying a new one? kniationoro24year. What is the probability- -1.55yr STD 0 A. 0.4090 B. 0.9890 C. 0.0110 D. 0.1587 Hi p-a 03 HG p=0.3 The test statistie is found to be 2.03. Which of the following is the correct p-value? 7. In testing the hypothesis -10P-o.3 H p/03 B. 0.0424 C.0.0212D. 1.9576 E. None of these A. 0.9788 A large company used a random sample of employees to estimate the cost of lunch in their cafeteria. A 25%confidencentenal for the true mean amount of money spent on lunch was found to be ($780. $920). Which of the following statements is correct? 8. 95% of employees pay between $780 and S920 for lunch. We are 95% confident that the population mean amount employees spend on lunch is between $780 and $920. A. B. C, we are 95% confidentthat any employee at the company vill spend between D. We are 95% confident that the sample mean amount employees spend on lunch is between $780 and $920. $780 and $920 on lunch.

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16) R^2 = 88.3%

In statistics, the correlation coefficient r measures the strength and direction of a linear relationship between two variables on a scatterplot. The value of r is always between +1 and –1. To interpret its value, see which of the following values your correlation r is closest to: Exactly –1.

R = sqrt(R^2)

R = sqrt(0.883)

R = - 0.9397

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