Assume the time required to pass through security at a particular airport follow
ID: 3324418 • Letter: A
Question
Explanation / Answer
a=5 and b=29 for uniform distribution
a) f(x)=x/(b-a)=x/(29-5)=x/24
b) mean is (a+b)/2=(29+5)/2=17
standard deviation is (b-a)/sqrt(12)=24/sqrt(12)=6.9282
c) P(x<23)=(23-5)/(29-5)=0.75
d) P(x>21)=(29-21)/(29-5)=0.3333
e) P(10<x<13)=(13-10)/(29-5)=0.125
f) for 0.75 =(x-5)/(29-5) we get x=23
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