Id inteting wheher the proportion of tems in population s argr 1. If we are inte
ID: 3324777 • Letter: I
Question
Id inteting wheher the proportion of tems in population s argr 1. If we are interested ting whether the proportion of items in population 1 is larger than the proportion of test items in population 2 by 10%, the a. null hypothesis should state Pi-P>0.1 b. null hypothesis should state Pi-P20 c. alternative hypothesis should state P -P2 0. d. alternative hypothesis should state P1-P2 2. When developing an interval estimate for the difference between two sample means, with sample sizes of n and na, a. ni must be equal to n2 b. ni must be smaller than n c. ni must be larger than n2 d. n and n can be of different sizes, Problem 1 Salary information regarding male and female employees of a large company is shown below. Female 36 41 72 Sample Size Male 64 Sample Mean Salary (in $1,000) Population Variance (o) Refer to Problem 1. An estimate of the difference between the means of the two populations is 128 3. a. -28 b. 3 c. 4 4. Refer to Problem 1. The standard error for the difference between the two means is a. 4 b. 7.46 c. 4.24 d. 2.0 5. Refer to Problem I. At 95% confidence, the margin of error is a. 1.96 b. 1.645 c. 3.920 d. 2.000 Refer to Problem I. The 95% confidence interval for the difference between the means of the two populations is a. b. c. -1.96 to 1.96 d. -0.92 to 6.92 6. 0 to 6.92 _2 to 2 Refer to Problem 1. If you are interested in testing whether or not the average salary of males is significantly greater than that of females, the test statistic is a. 2.0 b. 1.5 c. 1.96 d. 1.645 7.
Explanation / Answer
Solution:-
1. option c. alternative hypothesis should state P1 - P2 > 0.1
2. option d. n1 and n2 can be of different sizes,
problem 1
3. option b. 3
=> 44 - 41 = 3
4. option d. 2.0
=> Sqrt((128/64)+(72/36) = 2
5. option c.3.920
=> Z*SE = 1.96*2 = 3.92
6. option d. -0.92 to 6.92
=> (3-3.92 , 3+3.92) = (-0.92 , 6.92)
7. option b. 1.5
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